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Many gases are shipped in high pressure containers. What is the final volume of the gas, in milliliters, when the pressure and temp of the gas is changed to A.) 658 mmHg and 281K? B.) 0.55 atm and 75
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If the volume increases to 1,000.0 ml, what is the newĪ sample of argon gas has a volume of 735 mL at a pressure of 1.20 atm and a temp of 112 degrees Celsius. The pressure of a gas is 100.0 kPa and its volume is 500.0 ml. If the pressure is decreased to 0.75 atm, what is its new volume? 2. The volume of a gas is 10.0 liters and its pressure is 1.5 atm. I've tried using the ideal gas law: PV=nRT but i can't seem to get where I am getting lost. If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure of 6.00 x 104 atm, what would the volume of that gas be?Ĭalculate the Volume occupied by 1.5 moles of an ideal gas at 25 degrees Celsius and a pressure of 0.80 atm. Synthetic diamonds can be manufactured at pressures of 6.00 x 104 atm. The volume of the container is then reduced to half its original volume. 2NO2(g)⇌N2O4(g) When the system is at equilibrium, it contains NO2 at a pressure of 0.724 atm, and N2O4 at a pressure of 0.0524 atm. I got this answer by plugging in the values into the equationĬonsider the following reaction. What is the final pressure exerted by the gas? 1. I will be happy to critiqueĪ 0.65 mole quantity of O2 occupies 4.0 L at 20.◦C. If I raise the temperature to 350K and lower the pressure to 1.5 atm, what is the new volume of the gas? Use the combined gas law here. w = _ J now calculate the work done if thisĪ gas takes up a volume of 17 liters, has a pressure of 2.3 atm, and a temperature of 299K.
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Calculate the work, w, if the gas expands against a constant external pressure of 1.00 atm to a final volume of 20.0 L. (a) What is the temperature when the pressure is 0.0500 atm? �C (b) What is the pressure atĬonsider an ideal gas encloesd in a 1.00 L container at an internal pressure of 10.0 atm. The pressure in a constant-volume gas thermometer is 0.700 atm at 100�C and 0.512 atm at 0�C.